PAU-Selectividad Matemáticas II Andalucía 2006-3B

Resuelve

$\left( \begin{array}{ccc} 2 & 0 & 5 \\ 1 & 1 & -2 \\ -1 & 1 & 1 \end{array} \right) \left( \begin{array}{ccc} x \\ y \\ z \end{array} \right) + \left( \begin{array}{ccc} -2 \\ 2 \\ 3 \end{array} \right) = \left( \begin{array}{ccc} 5 \\ 0 \\ 2 \end{array} \right)$